If $f (x) = 2 x + 5$ $f(x)= 2x+5$ and $g (x) = x^{2} - 3$ $g(x)=x^2-3$ , how do you find [f o g] (x)?

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Answer 1 · 2017-05-16T02:12:13

$[f o g] (x) = 2 x^{2} - 1$ $[fog] (x) = 2x^2 - 1$

$f (x) = 2 x + 5, g (x) = x^{2} - 3$ $f(x) = 2 x + 5, g(x) = x^2 - 3$ then,

$[f o g] (x) = 2 (g (x)) + 5 = 2 (x^{2} - 3) + 5$ $[fog] (x) = 2 (g(x)) + 5 = 2(x^2 - 3) + 5$

$[f o g] (x) = 2 x^{2} - 6 + 5$ $[fog] (x) = 2x^2 - 6 + 5$

$[f o g] (x) = 2 x^{2} - 1$ $[fog] (x) = 2x^2 - 1$

If f(x)=2x+5f(x)= 2x+5 and g(x)=x2−3g(x)=x^2-3, how do you find [f o g] (x)?