Question

If `f(x+3)=[x+1]/[2x-1]` then how do you find f(x-1)?

Answer 1

`f(x-1)=(x-3)/(2x-9)`

Explanation:

Solution is to find `f(x)` first.

the given is `f(x+3)=(x+1)/(2x-1)`

try to locate `(x+3)` at the right side of the equation

`f(x+3)=(x+3-3+1)/(2(x+3-3)-1)` add 3 and subtract 3 where you can find x because it is the same as adding nothing. Then simplify retaining the (x+3)

`f(x+3)=(x+3-2)/(2(x+3)-6-1)=((x+3)-2)/(2(x+3)-7)`

so that (x+3) can now be changed to simply x

`f(x)=(x-2)/(2x-7)`

use (x-1) at this point in place of x in f(x)

`f(x-1)=(x-1-2)/(2(x-1)-7)`

`f(x-1)=(x-3)/(2x-9)`

Have a nice day from the Philippines !