If $f (x) = 3 x^{2} - 3 x$ $f(x)=3x^2 - 3x$ , what is f(0), f(-1) and f(2)?

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Answer 1 · 2017-05-04T06:48:32

$f (0) = 0$ $f(0)=0$
$f (- 1) = 6$ $f(-1)=6$
$f (2) = 6$ $f(2)=6$

$f (x) = 3 x^{2} - 3 x$ $f(x)=3x^2-3x$

$f (0) = 3 \cdot 0^{2} - 3 \cdot 0 = 0$ $f(0)=3*0^2-3*0=0$

$f (- 1) = 3 \cdot {(- 1)}^{2} - 3 \cdot (- 1) = 3 \cdot 1 + 3 = 6$ $f(-1)=3*(-1)^2-3*(-1)=3*1+3=6$

$f (2) = 3 \cdot 2^{2} - 3 \cdot 2 = 3 \cdot 4 - 6 = 12 - 6 = 6$ $f(2)=3*2^2-3*2=3*4-6=12-6=6$

If f(x)=3x^2 - 3xf(x)=3x2−3xf(x)=3x^2 - 3x, what is f(0), f(-1) and f(2)?