If #f(x) = 4x -2# and #g(x) = e^(-x-1)#, what is #f'(g(x)) #? Calculus Basic Differentiation Rules Chain Rule 1 Answer Astralboy Apr 16, 2017 #f'(g(x))=4# Explanation: First, take the derivative of #f(x)#: #f'(x)=4# Now plug in #g(x)# in for #x# in #f'(x)#. However, there's no #x#. So that means that: #f'(g(x))=4# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2168 views around the world You can reuse this answer Creative Commons License