If $f(x)=4x^3-4x^2+10$ then how do you find $f(-2)$ ?

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Answer 1 · 2015-02-06T00:02:27

Just put $-2$ in place of the $x$ 's

$f(x)=4*x^3-4*x^2+10$

So:
$f(-2)=4*(-2)^3-4*(-2)^2+10$
$=4*(-8)-4*(4)+10$
$=-32-16+10$
$=-38$

Answer :

$f(-2)=-38$

If f(x)=4x^3-4x^2+10f(x)=4x^3-4x^2+10 then how do you find f(-2)f(-2)?