If $f (x) = 4 x^{- 5}$ $f(x)=4x^-5$ and $g (x) = \frac{x^{3}}{4}$ $g(x)=x^3/4$ , then what is g(f(x))?

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If $f (x) = 4 x^{- 5}$ $f(x)=4x^-5$ and $g (x) = \frac{x^{3}}{4}$ $g(x)=x^3/4$ , then what is g(f(x))?

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Answer 1 · 2015-10-02T01:22:08

I found: $g [f (x)] = \frac{16}{x^{15}}$ $g[f(x)]=16/x^15$

Explanation:

I would use $f (x)$ $f(x)$ inside $g (x)$ $g(x)$ instead of $x$ $x$ as:
$g [f (x)] = \frac{{[4 x^{- 5}]}^{3}}{4} = \frac{4^{3}}{4} \cdot x^{- 15} = \frac{4^{2}}{x^{15}} = \frac{16}{x^{15}}$ $g[f(x)]=[color(red)(4x^-5)]^3/4=(4^3)/4*x^-15=4^2/x^15=16/x^15$

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If $f (x) = 4 x^{- 5}$ $f(x)=4x^-5$ and $g (x) = \frac{x^{3}}{4}$ $g(x)=x^3/4$ , then what is g(f(x))?

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If $f (x) = 4 x^{- 5}$ $f(x)=4x^-5$ and $g (x) = \frac{x^{3}}{4}$ $g(x)=x^3/4$ , then what is g(f(x))?