If $f (x) = 4 x^{- 5}$ $f(x)=4x^-5$ and $g (x) = \frac{x^{3}}{4}$ $g(x)=x^3/4$ , then what is g(g(x))?

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Answer 1 · 2018-04-06T04:32:58

$\frac{x^{9}}{256}$ $x^9/256$

$g (g (x)) = \frac{{(\frac{x^{3}}{4})}^{3}}{4} = \frac{\frac{x^{9}}{64}}{4} = \frac{x^{9}}{256}$ $g(g(x))=(x^3/4)^3/4=(x^9/64)/4=x^9/256$

If f(x)=4x−5f(x)=4x^-5 and g(x)=x34g(x)=x^3/4, then what is g(g(x))?