If $f (x) = 5 x$ $f(x)=5x$ , $g (x) = \frac{1}{x}$ $g(x)=1/x$ , and $h (x) = x^{3}$ $h(x)=x^3$ , how do you find $\frac{5 h (1) - 2 g (3)}{3 f (2)}$ $(5h(1)-2g(3))/(3f(2))$ ?

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If $f (x) = 5 x$ $f(x)=5x$ , $g (x) = \frac{1}{x}$ $g(x)=1/x$ , and $h (x) = x^{3}$ $h(x)=x^3$ , how do you find $\frac{5 h (1) - 2 g (3)}{3 f (2)}$ $(5h(1)-2g(3))/(3f(2))$ ?

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Answer 1 · 2016-01-28T04:17:47

$\frac{13}{90}$ $13/90$ , or $0.1 ¯ 4$ $0.1bar4$

Explanation:

$\frac{5 h (1) - 2 g (3)}{3 f (2)}$ $(5h(1) - 2g(3))/(3f(2))$

Now let's plug in the values for those functions:

$\frac{5 \cdot (1^{3}) - 2 \cdot (\frac{1}{3})}{3 \cdot (5 \cdot 2)}$ $(5*(1^3) - 2*(1/3))/(3*(5*2))$

$1^{3} = 1$ $1^3 = 1$ , and since any number times $1$ $1$ is the same, we can remove it.

$\frac{5 - 2 \cdot (\frac{1}{3})}{3 \cdot (5 \cdot 2)}$ $(5 - 2*(1/3))/(3*(5*2))$

Now we can simplify $2 \cdot (\frac{1}{3})$ $2*(1/3)$ to $\frac{2}{3}$ $2/3$

$\frac{5 - \frac{2}{3}}{3 \cdot (5 \cdot 2)}$ $(5 - 2/3)/(3*(5*2))$

And we can multiply the numbers in the denominator $3 \cdot 5 = 15$ $3*5 = 15$ , and $15 \cdot 2 = 30$ $15 *2 = 30$

$\frac{5 - \frac{2}{3}}{30}$ $(5 - 2/3)/30$

Now let's try and get rid of that ugly fraction in a fraction! We can do that by multiplying the entire fraction by $\frac{3}{3}$ $3/3$ which is also equal to $1$ $1$ , and like we said above, we're not actually changing the value by doing that!

$\frac{5 - \frac{2}{3}}{30} \cdot \frac{3}{3}$ $(5 - 2/3)/30 * 3/3$

Multiplying through on both sides:

$\frac{5 \cdot 3 - (\frac{2}{3}) \cdot 3}{30 \cdot 3}$ $(5*3 - (2/3)*3)/(30*3)$

Now simplify the multiplications:

$\frac{15 - 2}{90}$ $(15 - 2)/90$

Now subtract in the numerator... and...

$\frac{13}{90}$ $13/90$

There you have it!

Answer 2 · 2016-01-28T04:24:45

$\frac{13}{90}$ $13/90$

Explanation:

$\frac{5 h (1) - 2 g (3)}{3 f (2)}$ $(5h(1)-2g(3))/(3f(2))$
$= \frac{5 {(1)}^{3} - 2 (\frac{1}{3})}{3 (5 \cdot 2)}$ $=(5(1)^3-2(1/3))/(3(5*2)$
$= \frac{5 - \frac{2}{3}}{3 \cdot 10}$ $=(5-2/3)/(3*10)$
$= \frac{\frac{13}{3}}{30}$ $=(13/3)/30$
$= \frac{13}{3} \cdot \frac{1}{30}$ $=13/3*1/30$
$= \frac{13}{90}$ $=13/90$

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If $f (x) = 5 x$ $f(x)=5x$ , $g (x) = \frac{1}{x}$ $g(x)=1/x$ , and $h (x) = x^{3}$ $h(x)=x^3$ , how do you find $\frac{5 h (1) - 2 g (3)}{3 f (2)}$ $(5h(1)-2g(3))/(3f(2))$ ?

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Explanation:

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If f(x)=5xf(x)=5x, g(x)=1xg(x)=1/x, and h(x)=x3h(x)=x^3, how do you find 5h(1)−2g(3)3f(2)(5h(1)-2g(3))/(3f(2))?

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Explanation:

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If $f (x) = 5 x$ $f(x)=5x$ , $g (x) = \frac{1}{x}$ $g(x)=1/x$ , and $h (x) = x^{3}$ $h(x)=x^3$ , how do you find $\frac{5 h (1) - 2 g (3)}{3 f (2)}$ $(5h(1)-2g(3))/(3f(2))$ ?