Question

If `f(x) =-e^(-x-7)` and `g(x) = -2sec^2x`, what is `f'(g(x))`?

Answer 1

Please see below.

Explanation:

`f'(x) = -e^(-x-7) * d/dx(-x-7) = e^(-x-7)`

So

`f(g(x)) = e^(-g(x)-7) = e^(2sec^2x-7)`