If #f(x)= tan8 x # and #g(x) = e^(5x ) #, how do you differentiate #f(g(x)) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Shwetank Mauria Mar 31, 2016 #f(g(x))=40e^(5x)sec^2(8e^(5x))# Explanation: As #f(x)=tan8x# and #g(x)=e^(5x)# #f(g(x))=tan(8e^(5x))# and #(df)/(dx)=(d(tan8e^(5x)))/(d(8e^(5x)))*(d(8e^(5x)))/(dx)# = #sec^2(8e^(5x))*8*e^(5x)*5# = #40e^(5x)sec^2(8e^(5x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1249 views around the world You can reuse this answer Creative Commons License