If #f(x)= (x^2-9)/(x+3)# is continuous at #x= -3#, then what is #f(-3)#?
1 Answer
May 27, 2015
Apparently your function is not continuous at
But, if you write:
now you have:
so that now you have:
Your
so that basically
Graphically:
graph{(x^2-9)/(x+3) [-10, 10, -5, 5]}