If $g (x) = 2 x - 5$ $g(x) = 2x-5$ , how do you find g(1/3)?

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If $g (x) = 2 x - 5$ $g(x) = 2x-5$ , how do you find g(1/3)?

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Answer 1 · 2015-05-24T00:21:40

$g (\frac{1}{3})$ $g(1/3)$ means that instead of $x$ $x$ you have $\frac{1}{3}$ $1/3$ or that your function $g (x)$ $g(x)$ is evaluated in $x = \frac{1}{3}$ $x=1/3$ , so:
$g (\frac{1}{3}) = 2 \cdot \frac{1}{3} - 5 =$ $g(1/3)=2*1/3-5=$ and rearranging:
$= \frac{2 - 15}{3} = - \frac{13}{3}$ $=(2-15)/3=-13/3$

This means that your function $g (x)$ $g(x)$ has value equal to $- \frac{13}{3}$ $-13/3$ when $x = \frac{1}{3}$ $x=1/3$

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If $g (x) = 2 x - 5$ $g(x) = 2x-5$ , how do you find g(1/3)?

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If g(x)=2x−5g(x) = 2x-5, how do you find g(1/3)?

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If $g (x) = 2 x - 5$ $g(x) = 2x-5$ , how do you find g(1/3)?