If $g (x) = 3^{2} - x + 17$ $g (x) = 3^2 - x + 17$ , then how do you find g (2)?

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Answer 1 · 2015-07-07T22:46:13

In case there is an error in the question, lets look at $g (x) = x^{2} - x + 17$ $g(x) = x^2-x+17$

For $g (x) = x^{2} - x + 17$ $g(x) = x^2-x+17$

It may be helpful to think of it this way:

$g (x) = {(x)}^{2} - (x) + 17$ $g(color(red)(x)) = (color(red)(x))^2-(color(red)(x))+17$

To find $g (2)$ $g(2)$ , we will replace all of the $x$ $color(red)(x)$ 's with $2$ $color(red)(2)$ s.

$g (2) = {(2)}^{2} - (2) + 17$ $g(color(red)(2)) = (color(red)(2))^2-(color(red)(2))+17$

We get:

$g (2) = {(2)}^{2} - (2) + 17$ $g(2) = (2)^2 - (2) + 17$

$= 4 - 2 + 17$ $= 4-2+17$
$= 2 + 17$ $= 2+17$
$= 19$ $= 19$

That is: $g (2) = 19$ $g(2) = 19$

Note: I am convinced that the use of parentheses in the first step is a very good habit to develop.

If g(x)=32−x+17g (x) = 3^2 - x + 17, then how do you find g (2)?