If $g(x) = 9x^2+3x$ how do you find $g(-3)$ ?

Question

3629 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-18T04:14:31

$= 72$

We have to put $-3$ in place of $x$ . Given

$g(x)= 9x^2 +3x$

Putting $g = -3$

$g(-3) = 9(-3)^2 + 3(-3)$

$= 81 -9$

$= 72$

If g(x) = 9x^2+3xg(x) = 9x^2+3x how do you find g(-3)g(-3)?