If $g (x) = - x^{2} - 2 x - 4$ $g(x)=-x^2-2x-4$ , what is $g (0)$ $g(0)$ ?

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If $g (x) = - x^{2} - 2 x - 4$ $g(x)=-x^2-2x-4$ , what is $g (0)$ $g(0)$ ?

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Answer 1 · 2018-04-20T10:15:54

$g (0) = - 4$ $g(0)=-4$

Explanation:

$to evaluate g (0) substitute x = 0 into g (x)$ $"to evaluate "g(0)" substitute x = 0 into "g(x)$

$\Rightarrow g (0) = - 0^{2} - (2 \times 0) - 4 = - 4$ $rArrg(color(red)(0))=-color(red)(0)^2-(2xxcolor(red)(0))-4=-4$

Answer 2 · 2018-04-20T13:26:27

$- 4$ $-4$

Explanation:

Given: $g (x) = - x^{2} - 2 x - 4$ $g(x)=-x^2-2x-4$

For $g (0)$ $g(0)$ , plug in $x = 0$ $x=0$ into the function to get:

$g (0) = - 0^{2} - 2 \cdot 0 - 4$ $g(0)=-0^2-2*0-4$

$= 0 - 0 - 4$ $=0-0-4$

$= 0 - 4$ $=0-4$

$= - 4$ $=-4$

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If $g (x) = - x^{2} - 2 x - 4$ $g(x)=-x^2-2x-4$ , what is $g (0)$ $g(0)$ ?

2 Answers

Explanation:

Explanation:

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