If $h(x)=3^(2x)$ and $f(x)=x-2$ , how do you find $h(f(-3))$ ?

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Answer 1 · 2018-03-30T05:16:58

$h(f(-3))~=0.000017$

When we evaluate a function, we substitute in a value.

$h(f(x))$ means 'evaluate $f(x)$ first, then evaluate $h("that answer")$ '.

So first, we know $x=-3$

Then $f(x)=f(-3)$

We substitute in $-3$ where we see $x$ , so $f(-3)=(-3)-2=-5$

Now we evaluate $h(f(x))=h(-5)$ .

$h(x)=3^(2x)$ and we substitute in $-5$ wherever we see $x$ :

$h(x)=3^2(-5)=3^-10 =1/3^10~=0.000017$

If h(x)=3^(2x)h(x)=3^(2x) and f(x)=x-2f(x)=x-2, how do you find h(f(-3))h(f(-3))?