If $h (x) = \frac{x^{2} - 5 x - 6}{4 - x}$ $h(x)=(x^2-5x-6)/(4-x)$ , what is $h (- 1) . h (4)$ $h(-1). h(4)$ , and $h (2)$ $h(2)$ ?

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If $h (x) = \frac{x^{2} - 5 x - 6}{4 - x}$ $h(x)=(x^2-5x-6)/(4-x)$ , what is $h (- 1) . h (4)$ $h(-1). h(4)$ , and $h (2)$ $h(2)$ ?

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Answer 1 · 2017-06-13T11:26:40

$h (- 1) = 0$ $h(-1) = 0$ , $h (4) =$ $h(4) =$ Undefined , $h (2) = - 6$ $h(2) = -6$

Explanation:

$h (x) = \frac{x^{2} - 5 x - 6}{4 - x}$ $h(x) = (x^2-5x-6)/(4-x)$

$h (- 1) = \frac{{(- 1)}^{2} - 5 \cdot (- 1) - 6}{4 - (- 1)} = \frac{1 + 5 - 6}{4 + 1} = \frac{0}{5} = 0$ $h(-1) = ((-1)^2-5*(-1)-6)/(4-(-1)) = (1+5-6)/(4+1) =0/5=0$

$h (4) = \frac{4^{2} - 5 \cdot 4 - 6}{4 - 4} = \frac{- 10}{0} =$ $h(4) = (4^2-5*4-6)/(4-4) = (-10)/0 =$ Undefined

$h (2) = \frac{2^{2} - 5 \cdot 2 - 6}{4 - 2} = \frac{- 12}{2} = - 6$ $h(2) = (2^2-5*2-6)/(4-2) = (-12)/2 = -6$ [Ans]

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If $h (x) = \frac{x^{2} - 5 x - 6}{4 - x}$ $h(x)=(x^2-5x-6)/(4-x)$ , what is $h (- 1) . h (4)$ $h(-1). h(4)$ , and $h (2)$ $h(2)$ ?

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If h(x)=x2−5x−64−xh(x)=(x^2-5x-6)/(4-x), what is h(−1).h(4)h(-1). h(4), and h(2)h(2)?

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If $h (x) = \frac{x^{2} - 5 x - 6}{4 - x}$ $h(x)=(x^2-5x-6)/(4-x)$ , what is $h (- 1) . h (4)$ $h(-1). h(4)$ , and $h (2)$ $h(2)$ ?