Question

If I have 4.00 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

Answer 1

`T=(PV)/(nR)` `~=` `200*K`

Explanation:

We use the Ideal Gas equation, `PV=nRT`, and solve for `T`, which here has units of `"degrees Kelvin"`.

`T=(5.6*cancel(atm)xx12*cancel(L))/(0.0821*cancel(L)*cancel(atm)*K^-1*cancel(mol^-1)xx4.00*cancel(mol))`

We are left with units of `1/(K^-1)=K`, units of temperature as required.