If I have 4.00 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

1 Answer
anor277
Nov 3, 2016

T=(PV)/(nR)T=PVnR ~=≅ 200*K200⋅K

Explanation:

We use the Ideal Gas equation, PV=nRTPV=nRT, and solve for TT, which here has units of "degrees Kelvin"degrees Kelvin.

T=(5.6*cancel(atm)xx12*cancel(L))/(0.0821*cancel(L)*cancel(atm)*K^-1*cancel(mol^-1)xx4.00*cancel(mol))

We are left with units of 1/(K^-1)=K, units of temperature as required.

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