If I have 45 liters of helium in a balloon at 25 degress celcius and increase the tempurate to 55 degrees celcius what will the new volume be?

1 Answer
May 13, 2017

50.L

Explanation:

This is a problem involving the temperature-volume relationship of gases, which is represented by Charles's law:

V1T1=V2T2

Remember that T is the absolute temperature, so you must convert the temperature from Celcius to Kelvin:

25oC+273=298K
55oC+273=328K

Now, rearrange the equation to solve for V2 (the new volume):

V2=(V1)T2T1

and plug in the known values:

V2=45L328K298K=50.L

(The decimal place is present to emphasize there are two significant figures, otherwise it's arbitrary whether you're using one or two.)