Question

If limit of `f(x)=2` and `g(x)=3` as `x->c`, what the limit of `f(x)/g(x)` as `x->c`?

Answer 1

`2/3`.

Explanation:

We know that, `lim_(x to c) (f(x))/(g(x))={lim_(x to c)f(x)}/{lim_(x to c)g(x)}`, provided that,

`lim_(x to c)g(x)!=0`.

Given that, `lim_(x to c) f(x)=2 and lim_(x toc) g(x)=3!=0`,

`"The reqd. Lim"=2/3`.