Question

If q is inversely proportional to p, and q = 3 / 2 when p = 72 how do you write the equation?

Answer 1

`q=108/p`

Explanation:

`"the initial statement is "qprop 1/p`

`"to convert to an equation multiply by k the constant"`
`"of variation"`

`rArrq=kxx1/p=k/p`

`"to find k use the given condition"`

`q=k/prArrk=qp=3/2xx72=108`

`"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(q=108/p)color(white)(2/2)|)))`