If #r# and #s# can be any integers such that #s > 10# and #2r + s =15#, which of the following is the solution set for #r#? #r>=3#

Question

1 - #r>=0#
2 - #r>=2#
3 - #r<=0#
4 - #r<=2#

3653 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-01T16:22:50

Option 4)

Putting #s = 11# as the first integer greater than #10# into

#2r+s=15#

we get at

#2r+11 = 15# or

#r = 2#

then follows #r le 2# because as #s# increases, #r# decreases