Question

If sec x=3 and tan x=2sqrt 2, what are the values of sin x and cos ^2 x?

Answer 1

`sinx=2sqrt2/3, and, cos^2x=1/9`

Explanation:

We have, `tanx=sinx/cosx=sinx*secx`

Given that, `secx=3, tanx=2sqrt2`

Sub.ing, we get, `2sqrt2=3sinx rArr sinx=2sqrt2/3`

`cos^2x=1/sec^2x=1/(3)^2=1/9.`