If the equation of projection is #y=ax-bx^2#, find initial velocity(#u#) and angle of projection(#theta#)?
2 Answers
Given that the equation of projection is
Horizontal component of velocity of projection is
Vertical component of velocity of projection is
Let at the t th sec after its projection from origin its position be represented by the coordinates
So
Again
Combining [1] and[2] we get
Comparing equation [3] with the given equation we get
and
See below.
Explanation:
This is a typical kinematic problem. Assuming that the movement begins at the referential origin we have
where
Now the orbit equation is
This condition must be true for all
Now grouping coefficients
Now solving for
Now