If the first and third of three consecutive odd integers are added, the result is 57 less than five times the second integer. How do you find the third integer?

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Answer 1 · 2017-05-09T11:31:14

The third integer is #21#

Let the three consecutive odd integers be #2n-1 , 2n+1 and 2n+3#

By condition , # (2n-1) +(2n+3) = 5(2n+1) -57 # or

# 2n-1 +2n+3 = 10n + 5 -57 or 4n +2 =10n -52 or 6n =54 or n =9#

Three consecutive odd integers are # 2n-1= 17 , 2n+1= 19 and 2n+3 =21#

The third integer is #21# [Ans]