Question

If the initial of an ideal gas at 2.250 atm is 62.00°c, what final temperature would cause the pressure to be reduced to 1.750 atm?

Answer 1

`"260.5 K"`

Explanation:

From Gay Lussac’s Law

`color(white)(...)"P ∝ T"`

`"P"_1/"T"_1 = "P"_2/"T"_2`

`"T"_2 = "P"_2 × "T"_1/"P"_1`

`color(white)("T"_2) = 1.750 cancel"atm" × "(62.00 + 273) K"/(2.250 cancel"atm")`

`color(white)("T"_2) = 1.750 × "335 K"/2.250`

`color(white)("T"_2) = 260.5\ "K"`