If the initial temperature of an ideal gas at 2.250 atm is 62.00 "^oC, what final temperature would cause the pressure to be reduced to 1.500 atm?

1 Answer
anor277
Nov 3, 2016

With a constant amount of gas, P_1/T_1=P_2/T_2, according to Charles' Law.

Explanation:

So, we convert the temperatures to the absolute scale, and solve the quotient:

T_2=(T_1xxP_2)/P_1=(335.15*Kxx1.500*atm)/(2.250*atm)=223*K

You should convert this temperature back to the "Celsius scale". It is intuitively sound that a decrease in temperature should result in a decrease in temperature. Why?

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