If the initial volume of the bubbles in a diver's blood is 15 mL and the initial pressure is 12.75 atm, what is the volume of the bubbles when the diver has surfaced to 1.00 atm pressure?

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If the initial volume of the bubbles in a diver's blood is 15 mL and the initial pressure is 12.75 atm, what is the volume of the bubbles when the diver has surfaced to 1.00 atm pressure?

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Answer 1 · 2016-09-13T06:54:55

$V_{2} ≅ 200 \cdot m L$ $V_2~=200*mL$

Explanation:

At constant temperature, $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ . Thus $V_{2}$ $V_2$ $=$ $=$ $\frac{P_{1} V_{1}}{P_{2}}$ $(P_1V_1)/P_2$ .

And thus, $\frac{12.75 \cdot a t m}{1 \cdot a t m} \times 15 \cdot m L$ $(12.75*atm)/(1*atm)xx15*mL$ $=$ $=$ $? ?$ $??$

Of course, the temperature might have changed between depth and surface, but we have no way of interrogating this change. That diver is very deep $(> 100 \cdot m)$ $(>100*m)$ . Sports divers would never go near that depth.

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If the initial volume of the bubbles in a diver's blood is 15 mL and the initial pressure is 12.75 atm, what is the volume of the bubbles when the diver has surfaced to 1.00 atm pressure?

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