If the length of a 22 cm22cm spring increases to 55 cm55cm when a 7 kg7kg weight is hanging from it, what is the spring's constant?

1 Answer
Apr 7, 2016

K=208,09" N/mK=208,09Nm

Explanation:

G=m*g" "G=7*9,81" "G=68,67 " "NG=mg G=79,81 G=68,67 N

Delta x=55-22=33 cm=0,33 m
K:"spring constant"
G=K*Delta x

68,67=K*0,33

K=(68,67)/(0,33)

K=208,09" N/m