If the length of a $22 c m$ $22 cm$ spring increases to $95 c m$ $95 cm$ when a $7 k g$ $7 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2017-01-25T14:55:55

spring constant =93.97 $\frac{N}{m}$ $N/m$

Simply
using formula

$F = k \cdot x$ $F=k*x$
$k = \frac{f}{x}$ $k=f/x$
$k = 7 \cdot \frac{9.8}{95} - 22$ $k=7*9.8/95-22$
$k = 93.97 \frac{N}{m}$ $k=93.97N/m$

If the length of a 22cm22 cm spring increases to 95cm95 cm when a 7kg7 kg weight is hanging from it, what is the spring's constant?