If the length of a $24 c m$ $24 cm$ spring increases to $87 c m$ $87 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?

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If the length of a $24 c m$ $24 cm$ spring increases to $87 c m$ $87 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2018-05-11T16:39:22

$77.78 N/m$ $"77.78 N/m"$

Explanation:

Use this equation

$F = kx$ $"F = kx"$

Where

$F =$ $"F ="$ Force applied
$k =$ $"k ="$ Spring constant
$x =$ $"x ="$ Increase in length of spring

$k = \frac{F}{x} = \frac{mg}{x} = \frac{{5 kg \times 9.8 m/s}^{2}}{0.87 m - 0.24 m} = 77.78 N/m$ $"k" = "F"/"x" = "mg"/"x" = ("5 kg × 9.8 m/s"^2)/"0.87 m – 0.24 m" = "77.78 N/m"$

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If the length of a $24 c m$ $24 cm$ spring increases to $87 c m$ $87 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?

1 Answer

Explanation:

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Science

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Humanities

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If the length of a 24cm24 cm spring increases to 87cm87 cm when a 5kg5 kg weight is hanging from it, what is the spring's constant?

1 Answer

Explanation:

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Impact of this question

If the length of a $24 c m$ $24 cm$ spring increases to $87 c m$ $87 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?