Question

If the length of a `32 cm` spring increases to `71 cm` when a `4 kg` weight is hanging from it, what is the spring's constant?

Answer 1

`k~=100,62 N/m`

Explanation:

`Delta x=71-32=39 " cm"=0,39" m"`
`G=m*g=4*9,81=39,24N`
`G=k*Delta x`
`39,24=k* 0,39`
`k~=100,62 N/m`