If the length of a 34 cm spring increases to 45 cm when a 5 kg weight is hanging from it, what is the spring's constant?

1 Answer
May 25, 2016

K=445.91" "N/m

Explanation:

F=mg
F=K*Delta x
mg=K*Delta x

m=5" "kg
x_1=34" " cm
x_2=45" "cm
Delta x=x_2-x_1
Delta x=45-34
Delta x=11" "cm
Delta x=0.11" "m

5*9.81=0.11*K

K=(5*9.81)/(0.11)

K=445.91" "N/m