If the length of a $35 c m$ $35 cm$ spring increases to $73 c m$ $73 cm$ when a $3 k g$ $3 kg$ weight is hanging from it, what is the spring's constant?

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If the length of a $35 c m$ $35 cm$ spring increases to $73 c m$ $73 cm$ when a $3 k g$ $3 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2015-12-13T18:15:07

The spring constant will be $- 3 \frac{N}{m}$ $-3 N/m$

Explanation:

Given Data:

$D i s p l a c e m e n t (x) = 73 c m - 35 c m = 38 c m$ $Displacement (x) = 73 cm - 35 cm = 38 cm$
$= 38 \cdot 10^{- 3} m$ $= 38 * 10^-3 m$
$x = 0.38 m$ $x= 0.38 m$

We've just done this to get it into the SI units or MKS system.

Force (F) $= m \cdot a = 3 \cdot 0.38$ $= m*a = 3 * 0.38$
$F = 1.14 N$ $F = 1.14 N$

Spring Constant (k) = ?

We know:

Spring Constant (k) $= - \frac{F}{x}$ $= - F/x$

$k = - \frac{1.14}{0.38}$ $k = -1.14/0.38$

$k = - 3$ $k = -3$

This is our final answer.

The trick here and most of these types of questions, the answer will be the mass we multiplying in the force.

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If the length of a $35 c m$ $35 cm$ spring increases to $73 c m$ $73 cm$ when a $3 k g$ $3 kg$ weight is hanging from it, what is the spring's constant?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

If the length of a 35cm35 cm spring increases to 73cm73 cm when a 3kg3 kg weight is hanging from it, what is the spring's constant?

1 Answer

Explanation:

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Impact of this question

If the length of a $35 c m$ $35 cm$ spring increases to $73 c m$ $73 cm$ when a $3 k g$ $3 kg$ weight is hanging from it, what is the spring's constant?