If the length of a $37 c m$ $37 cm$ spring increases to $73 c m$ $73 cm$ when a $4 k g$ $4 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2017-07-12T08:08:52

The spring constant is $= 108.9 n m^{- 1}$ $=108.9nm^-1$

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The mass is $= 4 k g$ $=4kg$

The extension is $Deltax=0.73-0.37=0.36m$

The spring constant is

$k=F/(Deltax)=4g/0.36=108.9Nm^-1$

If the length of a 37 cm37cm37 cm spring increases to 73 cm73cm73 cm when a 4 kg4kg4 kg weight is hanging from it, what is the spring's constant?