If the length of a $44 c m$ $44 cm$ spring increases to $58 c m$ $58 cm$ when a $5 k g$ $5 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2016-02-04T14:13:56

$K = \frac{49, 05}{0, 14} = 350, 357142857 \frac{N}{m}$ $K=(49,05)/(0,14)=350,357142857 N/m$

$58 - 44 = 14 c m$ $58-44=14 cm$
$Delta x=14* 10^-2=0,14 meters$
$F=K*Delta x$
$5*9,81=K*0,14$
$49,05=K*0,14$
$K=(49,05)/(0,14)=350,357142857 N/m$

If the length of a 44 cm44cm44 cm spring increases to 58 cm58cm58 cm when a 5 kg5kg5 kg weight is hanging from it, what is the spring's constant?