If the length of a $49 cm$ spring increases to $84 cm$ when a $5 kg$ weight is hanging from it, what is the spring's constant?

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Answer 1 · 2015-12-09T17:43:03

$140"N/m"$

Hooke's Law states that:

$F=-kx$

$x$ is the extension which is $0.84-0.49=0.35"m"$

The force $=mg=5xx9.8"N"$

$:.k=F/x=(5xx9.8)/0.35=140"N/m"$

If the length of a 49 cm49 cm spring increases to 84 cm84 cm when a 5 kg5 kg weight is hanging from it, what is the spring's constant?