If the pressure is #8.314 * 10^4# #Pa#, #R# is #8.314#, the temperature is #100# #K#, and the number of moles of gas (#n#) is #300#, what is the volume of a gas in #m^3#?
1 Answer
Explanation:
Your tool of choice here will be the ideal gas law equation, which looks like this
#color(blue)(|bar(ul(color(white)(a/a)PV = nRTcolor(white)(a/a)|)))" "#
Here you have
#P# - the pressure of the gas
#V# - the volume it occupies
#n# - the number of moles of gas
#R# - the universal gas constant
#T# - the absolute temperature of the gas
Now, it's important to notice that the problem doesn't provide you with the units used for the universal gas constant. This means that you're going to have to do some research and see what units of
http://www.cpp.edu/~lllee/gasconstant.pdf
As you can see, you have
#R = 8.314color(white)(.) ("Pa m"^3)/("mol K")#
In this case, the units and the value match those given to you, so this is what you'll use in your calculations.
Your goal here is to figure out the volume of the gas, so rearrange the ideal gas law equation to solve for
#PV = nRT implies V = (nRT)/P#
Plug in your values to find
#V = (300 color(red)(cancel(color(black)("moles"))) * 8.314(color(red)(cancel(color(black)("Pa"))) * "m"^3)/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * 100color(red)(cancel(color(black)("K"))))/(8.314 * 10^4 color(red)(cancel(color(black)("Pa")))) = color(green)(|bar(ul(color(white)(a/a)color(black)("3 m"^3)color(white)(a/a)|)))#
The answer must be rounded to one sig fig.
