Question

If the pressure of 1.50 L of hydrogen gas at 100 °C decreases from 0.500 atm to 0.115 atm, what is the final volume? Assume temperature remains constant at 3.45 L.

Answer 1

`P_1V_1=P_2V_2`. `V_2~=6*L`

Explanation:

`V_2=(P_1V_1)/P_2` (and this will clearly give us an answer with units of volume as required.)

`V_2=(0.500*atmxx1.50*L)/(0.115*atm)=???`