If we throw a body vertically upwards with velocity 4 metres per second then at what height does its kinetic energy reduced to half of its initial value(10m/s^2)?

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Answer 1 · 2017-12-31T12:50:20

The height is #=0.8m#

The initial velocity is #u=4ms^-1#

The initial kinetic energy is

#KE=1/2m u^2#

AT the height #=hm#

The potential energy is

#PE=mgh#

#1/2KE=PE#

#1/2*1/2mv^2=mgh#

The acceleration due to gravity is #g=10ms^-2#

#h=(v^2/(2g))=4^2/(2*10)=0.8m#

The height is #=0.8m#