If (x+2) is a factor of x^3-6x^2+kx+10, what is k? Precalculus Real Zeros of Polynomials Synthetic Division 1 Answer Narad T. Jan 30, 2017 The answer is k=-11 Explanation: Let f(x)=x^3-6x^2+kx+10 If (x+2) is a factor Then, f(-2)=0 f(-2)=-8-24-2k+10=0 2k=-22 k=-11 Answer link Related questions What is synthetic division? What are common mistakes students make with synthetic division? How do I find the quotient and remainder using synthetic division? How do you write the remainder in synthetic division? How do I find the quotient (x^3+5x^2+x-15)/(x+3) by using synthetic division? How do I find the roots of a polynomial function by using synthetic division? How can synthetic division be used to factor a polynomial? How do I use synthetic division to find p(-3) for p(x)=x^4-2x^3-4x+4? Use synthetic division to find p(4) for p(x)=x^4-2x^3-4x+4? How do you use synthetic division to evaluate f(3) given that f(x)=x^3+2x^2-7x+8? See all questions in Synthetic Division Impact of this question 45503 views around the world You can reuse this answer Creative Commons License