Question

If `(x-2).P(x)= 3x^3+ax-10` , what is `P(-1)` ?

Answer 1

From `(x-2)P(x)=3x^3+ax-10` for `x=2` we get

`(2-2)P(2)=3*2^3+2a-10=>0=14+2a=>a=-7`

Hence the relation becomes

`(x-2)P(x)=3x^3-7x+10`

For `x=-1` then

`(-1-2)P(-1)=-3+7+10=>P(-1)=-14/3`