If x varies inversely with y and x = 4 when y = 9, how do you find x when y = 6?

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If x varies inversely with y and x = 4 when y = 9, how do you find x when y = 6?

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Answer 1 · 2018-04-18T15:04:24

$x = 6$ $x=6$

Explanation:

$the initial statement is x \propto \frac{1}{y}$ $"the initial statement is "xprop1/y$

$to convert to an equation multiply by k the constant$ $"to convert to an equation multiply by k the constant"$
$of variation$ $"of variation"$

$\Rightarrow x = k \times \frac{1}{y} = \frac{k}{y}$ $rArrx=kxx1/y=k/y$

$to find k use the given condition$ $"to find k use the given condition"$

$x = 4 when y = 9$ $x=4" when "y=9$

$x = \frac{k}{y} \Rightarrow k = x y = 4 \times 9 = 36$ $x=k/yrArrk=xy=4xx9=36$

$"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(x=36/y)color(white)(2/2)|)))$

$"when "y=6" then"$

$x=36/6=6$

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If x varies inversely with y and x = 4 when y = 9, how do you find x when y = 6?

1 Answer

Explanation:

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