If x varies inversely with y and x = 8 when y = 10, how do you find y when x = 6?

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Answer 1 · 2016-06-16T18:10:41

$y = 40/3 or 13 1/3$

This is an example of inverse proportion, or inverse variation.

To change a proportion into an equation, multiply by a constant and then use the values given to find the value of the constant.
$y prop 1/x$

$y = k/x rArr k = xy$

$k= 8 xx 10 = 80$

So, $y = (80)/x$

When $x = 6, " " y = (80)/(6)$

$y = 40/3 or 13 1/3$