If y=8, when x=4, how do you find x when y=2 given that y varies inversely as x?

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Answer 1 · 2017-01-23T09:03:40

16

#y# varies inversely as #x#

#=>y " " alpha" "1/x#

#=>y=k/x#

where #k# is the constant of proportionality

to find #k# we use the conditions given

#y=8,x=4#

#8=k/4=>k=32#

#:.y=32/x#

when #y=2#

#2=32/x=>x=32/2=16#