Question

If `y=sqrt(83.2x^3)` , find y'(1.74) ?

`y=sqrt(83.2x^3)`

Answer 1

`y'(1.74)=18.048`

Explanation:

If `y=f(x)`, `y'(x)=(dy)/(dx)`

as `y=sqrt(83.2x^3)=sqrt83.2x^(3/2)`

`y'=(dy)/(dx)=sqrt83.2xx3/2xxsqrtx`

and `y'(1.74)=sqrt83.2xx3/2xxsqrt1.74`

= `9.1214xx3/2xx1.3191`

= `18.048`