If y varies inversely as x and y = 40 when x = 16, how do you find y when x = 10?

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Answer 1 · 2018-04-26T05:53:56

$y=64$

The method for these questions always stays the same.
Follow the process below.

$y prop 1/x" "larr$ write as an inverse proportion

$y= k/x" "larr xx k$ to change it into an equation

$xy= k" "larr$ isolate $k$

$k = 16xx40 = 640" "larr$ substitute to find the value of $k$

$y = 640/x" "larr$ use the value for $k$ in the equation.

Now you can find a value for $x or$ y if you are given a value.

$x=10$

$y = 640/10$

$y=64$