If y varies inversely as x and y = 40 when x = 16, how do you find y when x = 10?

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Answer 1 · 2018-04-26T05:53:56

#y=64#

The method for these questions always stays the same.
Follow the process below.

#y prop 1/x" "larr# write as an inverse proportion

#y= k/x" "larr xx k# to change it into an equation

#xy= k" "larr# isolate #k#

#k = 16xx40 = 640" "larr# substitute to find the value of #k#

#y = 640/x" "larr# use the value for #k# in the equation.

Now you can find a value for #x or # y if you are given a value.

#x=10#

#y = 640/10 #

#y=64#