If y varies inversely as x and y=5 when x=3 how do you find x when y is 15?

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If y varies inversely as x and y=5 when x=3 how do you find x when y is 15?

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Answer 1 · 2017-09-08T12:35:14

$x = 1$ $x=1$

Explanation:

$the initial statement is y \propto \frac{1}{x}$ $"the initial statement is "yprop1/x$

$to convert to an equation multiply by k the constant of$ $"to convert to an equation multiply by k the constant of"$
$variation$ $"variation"$

$\Rightarrow y = \frac{k}{x}$ $rArry=k/x$

$to find k use the given condition$ $"to find k use the given condition"$

$y = 5 when x = 3$ $y=5" when "x=3$

$y = \frac{k}{x} \Rightarrow k = x y = 3 \times 5 = 15$ $y=k/xrArrk=xy=3xx5=15$

$"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=15/x)color(white)(2/2)|)))$

$"when "y=15$

$x=15/y=15/15=1$

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If y varies inversely as x and y=5 when x=3 how do you find x when y is 15?

1 Answer

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