Question

If you have exactly 1.00 L of sodium chloride solution that masses 1050 g, what is the molarity of the solution?

Answer 1

Approx. `1.4*mol*L^-1`.

Explanation:

There are `(1050-1000)*g` of solute in the AQUEOUS solution:

`"Concentration"` `=` `"Moles of solute"/"Volume of Solution"`

`=` `(50*g)/(36.46*g*mol^-1)xx1/(1.00*L)` `=` `??mol*L^-1`