In a mixture of oxygen and nitrogen gas, $80.0 %$ $80.0%$ of the total gas pressure is exerted by the nitrogen. If the total pressure is $2.0 atm$ $"2.0 atm"$ , what pressure does the oxygen exert?

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Answer 1 · 2018-03-20T01:11:37

$0.4 atm$ $"0.4 atm"$

$80 %$ $80%$ of pressure is exerted by nitrogen gas. So, $20 %$ $20%$ of pressure will be exerted by oxygen gas.

$p_{O_{2}} = 20 % of 2 atm = \frac{20}{100} \times 2 atm = 0.4 atm$ $"p"_("O"_2) = 20% "of 2 atm" = 20/100 × "2 atm" = "0.4 atm"$

In a mixture of oxygen and nitrogen gas, 80.0%80.0%80.0% of the total gas pressure is exerted by the nitrogen. If the total pressure is "2.0 atm"2.0 atm"2.0 atm", what pressure does the oxygen exert?